taap.digitalnetwork engineering toolkit

What is the wildcard mask for a /26?

Answer
0.0.0.63 wildcard for /26 (255.255.255.192)

A /26 has the subnet mask 255.255.255.192. Subtract it from 255.255.255.255 and you get the wildcard 0.0.0.63: the last 6 bits are "don't care", so it matches 64 consecutive addresses.

wildcard · adjust the values

The calculation

255.255.255.255 − 255.255.255.192 = 0.0.0.63

A /26 block is typically a 62-host segment such as a server or voice VLAN. With the network 10.0.0.0, the wildcard 0.0.0.63 matches 10.0.0.0 through 10.0.0.63.

Using it in Cisco IOS

! standard ACL
access-list 10 permit 10.0.0.0 0.0.0.63

! named extended ACL
ip access-list extended FROM-SITE
 permit ip 10.0.0.0 0.0.0.63 any

! OSPF
router ospf 1
 network 10.0.0.0 0.0.0.63 area 0

Junos, Arista EOS, MikroTik and Linux use the prefix form instead: 10.0.0.0/26.

Nearby prefixes

PrefixSubnet maskWildcardAddresses
/24255.255.255.00.0.0.255256
/25255.255.255.1280.0.0.127128
/26255.255.255.1920.0.0.6364
/27255.255.255.2240.0.0.3132
/28255.255.255.2400.0.0.1516

More questions like this

/16 → 0.0.255.255/17 → 0.0.127.255/18 → 0.0.63.255/19 → 0.0.31.255/20 → 0.0.15.255/21 → 0.0.7.255/22 → 0.0.3.255/23 → 0.0.1.255/24 → 0.0.0.255/25 → 0.0.0.127/27 → 0.0.0.31/28 → 0.0.0.15/29 → 0.0.0.7/30 → 0.0.0.3

Frequently asked questions

How many addresses does 0.0.0.63 match?

64. The wildcard has 6 one-bits, and 26 = 64.

Is 0.0.0.63 the same as 255.255.255.192?

No. 255.255.255.192 is the subnet mask; 0.0.0.63 is its bitwise inverse. Putting the subnet mask where IOS expects a wildcard matches the wrong addresses.